设A是4×3矩阵,r(A)=2,若B=
(102
020
-103),
求r(AB).
【正确答案】:|B|=
|1 0 2|
|0 2 0|
|-1 0 3|
=
|1 0 2|
|0 2 0|
|0 0 5|
=10≠0,
r(B)=3,则r(AB)=r(A)=2.
设A是4×3矩阵,r(A)=2,若B= (102 020 -103), 求r(AB).
- 2024-11-07 03:12:41
- 线性代数(工)(13175)