求级数∑n=1∞(2n+1)/n2(n+1)2的和.

求级数∑n=1(2n+1)/n2(n+1)2的和.
【正确答案】:因为(2n+1)/[n2(n+1)2]=(n2+2n+1-n2)/[n2(n+1)2] =1/n2-1/(n+1)2,所以s=limn→∞sn =limn→∞[(1-1/22)+(1/22-1/32)+…+(1/n2- 1/(n+1)2]=limn→∞(1-1/(n+1)2)=1.