设有向量组(I):α1=(1,1,0,0)T,α2=(0,1,1,0)T,α3=(0,0,1,1)T和向量组(Ⅱ):β1(2,1,1,2)T,β2(1,x,y,1)T,β3=(0,1,2,1)T.已知两个向量组(Ⅰ)与(Ⅱ)等价,求x、y的值.
【正确答案】:因为向量组(Ⅰ)与(Ⅱ)等价,所以由
(α1,α2,α3,β1,β2,β3)=
(1 0 0 2 1 0
1 1 0 1 x 1
0 1 1 1 y 2
0 0 1 2 1 1)
→
(1 0 0 2 1 0
0 1 0 -1 x-1 1
0 0 1 2 y-x+1 1
0 0 0 0 x-y 0),
得x=y(r(Ⅰ)=r(Ⅱ)).
由(β1,β2,β3,α1,α2,α3)=
(2 1 0 1 0 0
1 x 1 1 1 0
1 x 2 0 1 1
2 1 1 0 0 1)
→
(1 x 0 2 1 -1
0 1-2x 0 -3 -2 2
0 0 1 -1 0 1
0 0 0 0 0 0),
得1-2x≠0.所以有x-y≠1/2.
设有向量组(I):α1=(1,1,0,0)T,α2=(0,1,1,0)T,α3=(0,0,1,1)T和向量组(Ⅱ):β1(2,1
- 2024-11-07 03:13:18
- 线性代数(工)(13175)