求下列矩阵的秩：
(2-1211
11-102
25-4-29
33-1-18)
【正确答案】：A=
(2 -1 2 1 1
1 1 -1 0 2
2 5 -4 -2 9
3 3 -1 -1 8)
→
(1 1 -1 0 2
0 -3 4 1 -3
0 3 -2 -2 5
0 0 2 -1 2)
→
(1 1 -1 0 2
0 3 -2 -2 5
0 0 2 -1 2
0 0 2 -1 2)
→
(1 1 -1 0 2
0 3 -2 -2 5
0 0 2 -1 2
0 0 0 0 0)
r(A)=3．
求下列矩阵的秩： (2-1211 11-102 25-4-29 33-1-18)
- 2024-11-07 03:12:37
- 线性代数（工）(13175)