已知f(x,y)=x2y3+xy,求:fx(x,y),fy(x,y),fy(1,0),f(2,-1).
【正确答案】:fx(x,y)=2xy3+yxy-1,fx(1,0)=0. fy(x,y)=3x2y2+xylnx,fy(2,-1)=12+ln2/2.
已知f(x,y)=x2y3+xy,求:fx(x,y),fy(x,y),fy(1,0),f(2,-1).
- 2024-08-03 20:19:54
- 高等数学(工本)(00023)
- 1