复数[(3+2i)/(2-3i)]一[(3-2i)/(2+3i)]=()

复数[(3+2i)/(2-3i)]一[(3-2i)/(2+3i)]=()
B、2
C、一2i
D、2i
【正确答案】：D
【题目解析】：[(3+2i)/(2-3i)]一[(3-2i)/(2+3i)]=[(3+2i)(2+3i)]/[(2-3i)(2+3i)]—[(3-2i)(2-31)]/[(2-3i)(2+3i)]=(13i/13)-(-13i/13)=i+i=2i．